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प्रश्न
Write the degree of the differential equation (y''')2 + 3(y") + 3xy' + 5y = 0
उत्तर
The given differential equation is:
(y''')2 + 3(y") + 3xy' + 5y = 0
Here, highest order derivative is third order, which is raised to second-degree.
Hence, degree of this differential equation is 2.
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