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Question
A box contains 6 red marbles numbered 1 through 6 and 4 white marbles numbered from 12 through 15. Find the probability that a marble drawn is even numbered
Solution
Total number of marbles = (6 + 4) = 10
Let S be the sample space.
Then n(S) = number of ways of selecting one marble out of 10 = 10C1 = 10 ways
Let E3 = event of getting an even numbered marble
i.e. E3 = {2, 4, 6, 12, 14}
∴ n(E3) = 5
Hence, required probability = \[\frac{n\left( E_3 \right)}{n\left( S \right)} = \frac{5}{10} = \frac{1}{2}\]
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