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Question
A box contains 6 red marbles numbered 1 through 6 and 4 white marbles numbered from 12 through 15. Find the probability that a marble drawn is white and odd numbered .
Solution
Total number of marbles = (6 + 4) = 10
Let S be the sample space.
Then n(S) = number of ways of selecting one marble out of 10 = 10C1 = 10 ways
Let E2 = event of getting a white marble, which is odd numbered.
i.e. E2 = {13, 15}
∴ n(E2) = 2
Hence, required probability = \[\frac{n\left( E_2 \right)}{n\left( S \right)} = \frac{2}{10} = \frac{1}{5}\]
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