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Question
Two dice are thrown. Find the odds in favour of getting the sum 5.
Solution
Let A be the event of 'getting the sum 5'.
Then A= {(1, 4), (4, 1), (2, 3), (3, 2)}
Here, there are four favourable outcomes, while there are (36 – 4 =) 32 unfavourable outcomes.
∴ Odds in favour of the sum 5 = \[\frac{4}{32} = \frac{1}{8} = 1: 8\]
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