Question

In a simultaneous throw of a pair of dice, find the probability of getting a total greater than 8.

 

Answer 1

We know that in a single throw of two dices, the total number of possible outcomes is (6 × 6) = 36.
Let S be the sample space.
Then n(S) = 36

 Let E₁₆ = event of getting a total greater than 8
Then E₁₆ = {(3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6)}
         i.e. n (E₁₆) = 10

\[\therefore P\left( E_{16} \right) = \frac{n\left( E_{16} \right)}{n\left( S \right)} = \frac{10}{36} = \frac{5}{18}\]