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Question
A dice is thrown. Find the probability of getting:
2 or 4
Solution
The sample space of the given experiment is given by
S = {1, 2, 3, 4, 5, 6}
∴ n (S) = 6
Let B be the event of occurrence of the number 2 or 4.
Then B = {2,4}
i.e. n (B) = 2
\[\therefore P\left( B \right) = \frac{\text{ Number of outcomes favourable to B} }{\text{ Total number of possible outcomes }} = \frac{n\left( B \right)}{n\left( S \right)} = \frac{2}{6} = \frac{1}{3}\]
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