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Question
A flag pole ‘h’ metres is on the top of the hemispherical dome of radius ‘r’ metres. A man is standing 7 m away from the dome. Seeing the top of the pole at an angle 45° and moving 5 m away from the dome and seeing the bottom of the pole at an angle 30°. Find the height of the pole `(sqrt(3) = 1.732)`
Solution
Height of the Flag pole (ED) = h m
AF and AD is the radius of the semi circle (r)
AC = (r + 7)
AB = (r + 7 + 5)
= (r + 12)
In the right ∆ABD, tan 30° = `"AD"/"AB"`
`1/sqrt(3) = r/("r" + 12)`
`sqrt(3` r = r + 12
`sqrt(3)` r − r = 12
⇒ `"r" (sqrt(3) - 1)` = 12
r[1.732 – 1] = 12
⇒ 0.732r = 12
r = `12/(0.732)` ⇒ = 16.39 m
In the right ∆ACE, tan 45° = `"AE"/"AC"`
`1 + ("r" + "h")/("r" + 7)`
r + 7 = r + h
∴ h = 7 m
Height of the pole (h) = 7 m
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