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Question
Answer the following:
Find the equation of the tangent to the parabola y2 = 8x at t = 1 on it
Solution
Given equation of the parabola is y2 = 8x
Comparing this equation with y2 = 4ax, we get
4a = 8
∴ a = `8/4` = 2
t = 1
Equation of tangent with parameter t is
yt = x + at2
∴ The equation of tangent with t = 1 is
y(1) = x + 2(1)2
∴ y = x + 2
∴ x – y + 2 = 0
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