English

Evaluate the following Limits: limx→0ex+e-x-2x2 - Mathematics and Statistics

Advertisements
Advertisements

Question

Evaluate the following Limits: `lim_(x -> 0) ("e"^x + e^(-x) - 2)/x^2`

Sum

Solution

`lim_(x -> 0) ("e"^x + e^(-x) - 2)/x^2`

= `lim_(x -> 0) ("e"^x + 1/"e"^x - 2)/x^2`

= `lim_(x -> 0) (("e"^x)^2 + 1 - 2"e"^x)/(x^2*"e"^x`

= `lim_(x -> 0) ((e^x - 1)^2)/(x^2*"e"^x)`

= `lim_(x -> 0) [(("e"^x - 1)/x)^2 xx 1/"e"^x]`

= `lim_(x -> 0) (("e"^x - 1)/x)^2 xx 1/(lim_(x -> 0) "e"^x`

= `(1)^2 xx 1/"e"^0     ...[lim_(x -> 0) ("e"^x - 1)/x = 1]`

= `1 xx 1/1`

= 1

shaalaa.com
Limits of Exponential and Logarithmic Functions
  Is there an error in this question or solution?
Chapter 7: Limits - MISCELLANEOUS EXERCISE - 7 [Page 106]

APPEARS IN

Balbharati Mathematics and Statistics 1 (Commerce) [English] 11 Standard Maharashtra State Board
Chapter 7 Limits
MISCELLANEOUS EXERCISE - 7 | Q II. 12) | Page 106

RELATED QUESTIONS

Evaluate the following: `lim_(x -> 0)[(log(2 + x) - log( 2 - x))/x]`


Evaluate the following: `lim_(x -> 0) [(2^x - 1)^2/((3^x - 1) xx log (1 + x))]`


Evaluate the following Limits: `lim_(x -> 0)((1 - x)^5 - 1)/((1 - x)^3 - 1)`


Evaluate the following Limits: `lim_(x -> 0)[(x(6^x - 3^x))/((2^x - 1)*log(1 + x))]`


Evaluate the following Limits: `lim_(x -> 0)[(log 100 + log (0.01 + x))/x]`


Evaluate the following limit : 

`lim_(x -> 0) [(5^x + 3^x - 2^x - 1)/x]`


Evaluate the following limit : 

`lim_(x -> 0) [(6^x + 5^x + 4^x - 3^(x + 1))/sinx]`


Evaluate the following limit : 

`lim_(x ->0) [("a"^x - "b"^x)/(sin(4x) - sin(2x))]`


Evaluate the following limit : 

`lim_(x -> 0)[(15^x - 5^x - 3^x + 1)/(x*sinx)]`


Evaluate the following limit : 

`lim_(x -> 0) [((25)^x - 2(5)^x + 1)/(x*sinx)]`


Select the correct answer from the given alternatives.

`lim_(x -> 0) [(log(5 + x) - log(5 - x))/sinx]` =


Select the correct answer from the given alternatives.

`lim_(x→0)[(3^(sinx) - 1)^3/((3^x - 1).tan x.log(1 + x))]` =


Select the correct answer from the given alternatives.

`lim_(x -> 3) [(5^(x - 3) - 4^(x - 3))/(sin(x - 3))]` =


Evaluate the following :

`lim_(x -> 0)[("e"^x + "e"^-x - 2)/(x*tanx)]`


Evaluate the following :

`lim_(x -> 1) [("ab"^x - "a"^x"b")/(x^2 - 1)]`


`lim_(x -> 0) (log(1 + (5x)/2))/x` is equal to ______.


Evaluate the following:

`lim_(x->0)[((25)^x -2(5)^x+1)/x^2]`


Evaluate the following:

`lim_(x->0)[((25)^x - 2(5)^x + 1)/x^2]`


Evaluate the limit: 

`lim_(z->2)[(z^2-5x+6)/(z^2-4)]`


Evaluate the following:

`lim_(x->0)[((25)^x - 2(5)^x + 1)/x^2]`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×