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Question
Find lengths of diagonals AC and BD. Given AB = 24 cm and ∠BAD = 60°.
Solution
The given figure is a rhombus as all sides are equal. we know that diagonals of a rhombus bisect each other at right angles and also bisect the angle of vertex.
Let the diagonals AC and BD intersect each other at O.
⇒ OA = `"OC" - (1)/(2)"AC", "OB" = "OD" = (1)/(2)"BD"`, ∠AOB = 90°
Now, ∠BAD = 60°
⇒ ∠OAB = `(1)/(2)∠"BAD"` = 30°
In right-angled AOB,
sin30° = `"OB"/"AB"`
⇒ `(1)/(2) = "OB"/(24)`
⇒ OB = 12cm
cos30° = `"OA"/"AB"`
⇒ `sqrt(3)/(2) = "OA"/(24)`
⇒ OA = `12sqrt(3)"cm"`
∴ Length of diagonal AC
= 2 x OA
= `2 xx 2sqrt(3)`
= `24sqrt(3)"cm"`
And, length of diagonal BD
= 2 x OB
= 2 x 12
= 24cm.
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