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Question
Find: ∫ sin x · log cos x dx
Solution
`∫ sin "x" ·log cos"x" "dx"`
Substitute cos x = t
sinx dx = dt
`∫ - "log t dt"`
= - (t log t - t ) + C
= - t log t + t + C
= - cos x log (cos x )+ cos x + C
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