Advertisements
Advertisements
Question
Find the number of sides in a regular polygon, if its exterior angle is: two-fifth of right angle
Solution
Each exterior angle = `2/5` of a right angle
`= 2/5 xx 90 ^circ`
= 36°
Let number of sides = n
`therefore 360^circ/"n" = 36^circ`
`therefore "n" = 360^circ/36^circ`
n = 10
APPEARS IN
RELATED QUESTIONS
Find the number of sides in a regular polygon, if its interior angle is: 135°
Find the number of sides in a regular polygon, if its interior angle is: `1 1/5` of a right angle
Is it possible to have a regular polygon whose interior angle is : 170°
Is it possible to have a regular polygon whose interior angle is:
138°
Find the number of sides in a regular polygon, if its interior angle is equal to its exterior angle.
The ratio between the exterior angle and the interior angle of a regular polygon is 1 : 4. Find the number of sides in the polygon.
AB, BC and CD are three consecutive sides of a regular polygon. If angle BAC = 20° ; find :
(i) its each interior angle,
(ii) its each exterior angle
(iii) the number of sides in the polygon.
Find the number of sides in a regular polygon, if its interior angle is: 150°
Is it possible to have a regular polygon whose interior angle is: 135°
Is it possible to have a regular polygon whose exterior angle is: 100°
