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Question
Find the value of `("i"^6 + "i"^7 + "i"^8 + "i"^9)/("i"^2 + "i"^3)`
Solution
`("i"^6 + "i"^7 + "i"^8 + "i"^9)/("i"^2 + "i"^3)`
= `("i"^6(1 + "i" + "i"^2 + "i"^3))/("i"^2(1 + "i"))`
= `("i"^4(1 + "i" - 1 - "i"))/(1 + "i")` ...[∵ i2 = – 1 and i3 = – i]
= `("i"^4(0))/(1 + "i")`
= 0.
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