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Question
Find the value of the given expression.
`tan(sin^(-1) 3/5 + cot^(-1) 3/2)`
Solution
Let A = `sin^(-1) (3/5) "and" B = cot^(-1) (3/2)`
`sin A = 3/5 "and" cot B = 3/2`
`= tan A = 3/4 "and" tan B = 2/3`
`tan [tan^-1 (3/4) + tan^-1 (2/3)] = [tan^-1((3/4 + 2/3)/(1 - 3/4 xx 2/3))]`
`= tan [tan^-1(((9+8)/12)/(1 - 1/2))]`
`= tan [tan^-1 (17/6)]`
`= 17/6`
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