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If AB = BA for any two square matrices, prove by mathematical induction that (AB)n = AnBn - Mathematics

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Question

If AB = BA for any two square matrices, prove by mathematical induction that (AB)n = AnBn 

Sum

Solution

Let P(n): (AB)n = AnBn

So, P(1): (AB)1 = A1B1

⇒ AB = AB

So, P(1) is true.

Let P(n) is true for some k ∈ N

So, P(k): (AB)k = AkBk, k ∈ N  .....(i)

Now (AB)k+1 = (AB)k(AB)  ....(Using (i))

= AkBk(AB)

= AkBk–1(BA)B

= AkBk–1(AB)B   .....(As given AB = BA)

= AkBk–1AB2

= AkBk–2(BA)B2

= AkBk–2ABB2

= AkBk–2AB3

.......

.......

= Ak+1Bk+1

Thus P(1) is true and whenever P(k) is true P(k + 1) is true.

So, P(n) is true for all n ∈ N.

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Chapter 3: Matrices - Exercise [Page 58]

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NCERT Exemplar Mathematics [English] Class 12
Chapter 3 Matrices
Exercise | Q 49 | Page 58

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