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Question
If A and B are square matrices of the same order, explain, why in general
(A − B)2 ≠ A2 − 2AB + B2
Solution
\[\left( ii \right) LHS = \left( A - B \right)^2 \]
\[ = \left( A - B \right)\left( A - B \right)\]
\[ = A\left( A - B \right) - B\left( A - B \right)\]
\[ = A^2 - AB - BA + B^2\]
We know that a matrix does not have commutative property. So,
AB ≠ BA
Thus,
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