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Question
If f(x) = `{(x^2 + 3, x ≤ 2),(5x + 7, x > 2):}`, then find f(0)
Solution
f(x) = `{(x^2 + 3, x ≤ 2),(5x + 7, x > 2):}`
f(0) = 02 + 3
= 3
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