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Question
If f(x) = `{(x^2 + 3, x ≤ 2),(5x + 7, x > 2):}`, then find f(2)
Solution
f(x) = x2 + 3, x ≤ 2
∴ f(2) = [x2 + 3]x=2
= 22 + 3
= 7.
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