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Question
In a trapezium the parallel sides are 12cm and 8cm. If the distance between them is 6cm, find the area of the trapezium.
Solution
Area of a Trapezium = `(1)/(2)("a" + "b") xx "h"`,
Where a and b are the lengths of its parallel sides and h the perpendicular distance between them
here, a = 12cm, b = 8cm and h = 6cm
∴ Area of Trapezium
= `(1)/(2)(12 + 8) xx 6`
= `(1)/(2)(20) xx 6`
= 10 x 6
= 60cm2.
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