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Question
In the adjoining figure, ΔABC is right-angled at B and ∠A = 300. If BC = 6cm, find (i) AB, (ii) AC.
Solution
From the given right-angled triangle, we have:
`(BC)/(AB)= tan 30^0`
⇒`6/(AB) = 1/sqrt(3)`
⇒ `AB = 6 sqrt(3) cm`
Also, `(BC)/(AC) = sin 30^0`
⇒`6/(AC)=1/2`
⇒ `AC = (2xx6)=12 cm `
∴ AB = 6`sqrt(3)` cm and AC = 12 cm
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