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Question
If cos A = `3/5`, then find the value of `(sin"A" - cos"A")/(2tan"A")`
Solution
cos A = `3/5`
ΔABC
BC2 = AC2 – AB2
= 52 – 32
= 25 – 9
= 16
BC = `sqrt(16)` = 4
sin A = `4/5`, tan A = `4/3`
`(sin"A" - cos"A")/(2tan"A") = 4/5 - 3/5 ÷ 2(4/3)`
= `(4 - 3)/5 ÷(8/3)`
= `1/5 xx (3/8)`
= `3/40`
∴ The value of `(sin"A" - cos"A")/(2tan"A") = 3/40`
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