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Question
In following fig., ABCD is a square. A cirde is drawn with centre A so that it cuts AB and AD at Mand N respectively. Prove that Δ DAM ≅ Δ .BAN.
Solution
In Δ DAM and Δ BAN
AN = AM (radii of same circle)
AD = AB (sides of square ABCD)
∠ DAM = ∠ BAN (common)
∴ Δ DAM ≅ Δ BAN.
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