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Question
In following fig., PT is a tangent to the circle at T and PAB is a secant to the same circle. If PB = 9cm and AB = Scm, find PT.
Solution
Let PT = x cm
Since, PAB is a secant and PT is a tangent to the given circle, we have,
PA · PB = PT2
⇒ 4 · 9 = PT2
⇒ PT2 = 36
⇒ PT = 6cm
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