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Question
In Given Figure, find tan P – cot R.
Solution
Applying Pythagoras theorem for ΔPQR, we obtain
PR2 = PQ2 + QR2
(13 cm)2 = (12 cm)2 + QR2
169 cm2 = 144 cm2 + QR2
25 cm2 = QR2
QR = 5 cm
tan P = `("Side opposite to ∠P")/("Side adjacent to ∠P") = ("QR")/("PQ")`
= `5/12`
cot R = `("Side opposite to ∠R")/("Side adjacent to ∠R") = ("QR")/("PQ")`
= `5/12`
tan P - cot R = `5/12 - 5/12 = 0`
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