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Question
In the given figure, AD is a diameter. O is the centre of the circle. AD is parallel to BC and ∠CBD = 32°.
Find: ∠AOB
Solution
AD is parallel to BC, i.e., AO is parallel to BC and OB is transversal.
⇒ ∠ AOB = ∠ OBC ......(Alternate angles)
⇒ ∠ OBC = ∠ OBD + ∠ DBC
⇒ ∠OBC = 32° + 32°
⇒ ∠OBC = 64°
⇒ ∠ AOB = 64°
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