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Question
In the given figure, find the values of x, y and z.
Solution
In the give figure, ∠BAD = 60°, ∠ABD = 60°, ∠ADB = x, ∠DAC = 30°, ∠ADC = y and ∠ACD = z
We know that, the sum of all angles in a triangle is equal to 180°
In ΔABD, ∠BAD + ∠ABD + ∠ADB = 180°
⇒ 60° + 60° + x = 180°
⇒ 120° + x = 180°
⇒ x = 180° – 120°
⇒ x = 60°
Now, y = ∠BAD + ∠ABD ......[∵ Exterior angle is equal to the sum of interior opposite angles]
⇒ y = 60° + 60°
∴ y = 120°
In ΔADC, ∠DAC + ∠ADC + ∠ACD = 180° ......[Angle sum property of a triangle]
⇒ 30° + 120° + z = 180°
⇒ 150° + z = 180°
⇒ z = 180° – 150°
⇒ z = 30°
Hence, x = 60°, y = 120° and z = 30°.
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