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Proved that Cosec2(90° - θ) - Tan2 θ = Cos2(90° - θ) + Cos2 θ. - Mathematics

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Question

Proved that cosec2(90° - θ) - tan2 θ = cos2(90° - θ)  +  cos2 θ.

Sum

Solution

LHS = cosec2(90° - θ) - tan2 θ

LHS = secθ - tan2 θ = 1

RHS = cos2(90° - θ) + cos2 θ

RHS = sin2θ + cos2 θ = 1 

Hence, LHS = RHS

Hence proved.

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Chapter 18: Trigonometry - Exercise 2

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ICSE Mathematics [English] Class 10
Chapter 18 Trigonometry
Exercise 2 | Q 53.4
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