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Question
Solve for x.
log2 + log(x + 3) – log(3x – 5) = log3
Solution
log2 + log(x + 3) – log(3x – 5) = log3
∴ log [2(x + 3)] – log(3x – 5) = log3
∴ `log[(2x + 6)/(3x - 5)]` = log3
∴ `(2x + 6)/(3x - 5)` = 3
∴ 2x + 6 = 9x – 15
∴ 7x = 21
∴ x = 3
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