Question

The angle of elevation of the top of a 15 m high tower at a point ${\displaystyle 15\sqrt{3}}$ m away from the base of the tower is ______.

Options

• 30°

• 45°

• 60°

• 90°

Answer 1

The angle of elevation of the top of a 15 m high tower at a point ${\displaystyle 15\sqrt{3}}$ m away from the base of the tower is 30°.

Explanation:

Let the angle be x

So, tan x = ${\displaystyle \frac{15}{15\sqrt{3}}}$

= ${\displaystyle \frac{1}{\sqrt{3}}}$

${\displaystyle \Rightarrow }$ tan x = tan 30°

So, Angle of elevation = 30°