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प्रश्न
Answer the following:
Find the range of the following function.
f(x) = `1/(1 + sqrt(x))`
उत्तर
f(x) = `1/(1 + sqrt(x))` = y, (say)
∴ `sqrt(x) y + y` = 1
∴ `sqrt(x) = (1 - y)/y ≥ 0`
∴ `(y - 1)/y ≤ 0`
∴ 0 < y ≤ 1
Range = (0, 1]
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