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As observed from the top of a 75 m high lighthouse from the sea-level, the angles of depression of two ships are 30° and 45°. - Mathematics

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प्रश्न

As observed from the top of a 75 m high lighthouse from the sea-level, the angles of depression of two ships are 30° and 45°. If one ship is exactly behind the other on the same side of the lighthouse, find the distance between the two ships.

योग

उत्तर

Let AB be the lighthouse and the two ships be at point C and D respectively.

In ΔABC,

`"AB"/"BC"` = tan 45°

`75/"BC"` = 1

BC = 75 m

In ΔABD,

`"AB"/"BD"` = tan 30°

`75/("BC" + "CD") = 1/sqrt3`

`75/(75+"CD") = 1/sqrt3`

`75sqrt3 = 75 + "CD"`

`75(sqrt3 -1)"m" = "CD"`

If we take the value of `sqrt3` = 1.73

`75(1.73 -1)"m"`

= 54.91 m.

Hence, the Distance between the two ships is 54.91 m.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Some Applications of Trigonometry - Exercise 9.1 [पृष्ठ २०४]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 10
अध्याय 9 Some Applications of Trigonometry
Exercise 9.1 | Q 13 | पृष्ठ २०४
आरडी शर्मा Mathematics [English] Class 10
अध्याय 12 Trigonometry
Exercise 12.1 | Q 29 | पृष्ठ ३१

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