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Evaluate tan-1(sin(-π2)). - Mathematics

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प्रश्न

Evaluate `tan^-1(sin((-pi)/2))`.

योग

उत्तर

`tan^-1(sin((-pi)/2)) = tan^-1(-sin(pi/2))`

= `tan^-1(-1)`

= `- pi/4`.

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अध्याय 2: Inverse Trigonometric Functions - Solved Examples [पृष्ठ २१]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
अध्याय 2 Inverse Trigonometric Functions
Solved Examples | Q 2 | पृष्ठ २१

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