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Find the Equation of the Right Bisector of the Line Segment Joining the Points (3, 4) and (−1, 2). - Mathematics

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प्रश्न

Find the equation of the right bisector of the line segment joining the points (3, 4) and (−1, 2).

संक्षेप में उत्तर

उत्तर

Let A (3, 4) and B (−1, 2) be the given points.
Let C be the midpoint of AB.

C(312,4+22)(1,3)

 Slope of AB =2413=12

 Slope of the perpendicular bisector of AB =2

Thus, the equation of the perpendicular bisector of AB is

y3=2(x1)

2x+y5=0

Hence, the required line is 2x+y5=0.

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अध्याय 23: The straight lines - Exercise 23.12 [पृष्ठ ९३]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 23 The straight lines
Exercise 23.12 | Q 18 | पृष्ठ ९३

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