Advertisements
Advertisements
प्रश्न
Find the inverse of the following matrix (if they exist):
`[(3,-10),(2,-7)]`
उत्तर
Let A = `[(3,-10),(2,-7)]`
∴ |A| = `|(3,-10),(2,-7)| = - 21 + 20 = - 1 ne 0`
∴ A-1 exists.
Consider AA-1 = I
∴ `[(3,-10),(2,-7)] "A"^-1 = [(1,0),(0,1)]`
By R1 - R2, we get,
∴ `[(1,-3),(2,-7)] "A"^-1 = [(1,-1),(0,1)]`
By R2 - 2R1, we get,
`[(1,-3),(0,-1)] "A"^-1 = [(1,-1),(-2,3)]`
By (- 1)R2, we get,
`[(1,-3),(0,1)] "A"^-1 = [(1,-1),(2,-3)]`
By R1 + 3R2, we get,
`[(1,0),(0,1)] "A"^-1 = [(7,-10),(2,-3)]`
∴ `"A"^-1 = [(7,-10),(2,-3)]`
APPEARS IN
संबंधित प्रश्न
Find the inverse of the following matrix by elementary row transformations if it exists.
`A = [(1, 2, -2), (0, -2, 1), (-1, 3, 0)]`
Find the matrix of the co-factor for the following matrix.
`[(1,3),(4,-1)]`
Find the adjoint of the following matrix.
`[(2,-3),(3,5)]`
Find the adjoint of the following matrix.
`[(1, -1, 2),(-2, 3, 5),(-2, 0, -1)]`
Find the inverse of the following matrix by the adjoint method.
`[(-1,5),(-3,2)]`
Find the inverse of the following matrix (if they exist):
`((1,-1),(2,3))`
Choose the correct answer from the given alternatives in the following question:
If A = `[(1,2),(3,4)]`, and A (adj A) = kI, then the value of k is
Choose the correct answer from the given alternatives in the following question:
If A = `[(lambda,1),(-1, -lambda)]`, and A-1 does not exist if λ = _______
Choose the correct answer from the given alternatives in the following question:
The inverse of a symmetric matrix is
Find the inverse of the following matrices by the adjoint method `[(3, -1),(2, -1)]`.
Find the inverse of the following matrices by transformation method: `[(1, 2),(2, -1)]`
Find the inverse of A = `[(1, 0, 1),(0, 2, 3),(1, 2, 1)]` by elementary column transformations.
If A is a no singular matrix, then det (A–1) = _______
State whether the following is True or False :
A = `[(2, 1),(10, 5)]` is invertible matrix.
The adjoint matrix of `[(3, -3, 4),(2, -3, 4),(0, -1, 1)]` is ______.
If `[(x - y - z),(-y + z),(z)] = [(0),(5),(3)]`, then the value of x, y and z are respectively ______
If A = `[(1, -1, 1),(2, 1, -3),(1, 1, 1)]`, 10B = `[(4, 2,2),(-5, 0, ∞),(1, -2, 3)]` and B is the inverse of matrix A, then α = ______
If A is invertible matrix of order 3 and |A| = 5, then find |adj A|
If A = `[(0, 1),(2, 3),(1, -1)]` and B = `[(1, 2, 1),(2, 1, 0)]`, then find (AB)−1
If A = `[(1, 0, 0),(3, 3, 0),(5, 2, -1)]`, find A−1 by the adjoint method
If A = [aij]2×2, where aij = i – j, then A = ______
The value of Minor of element b22 in matrix B = `[(2, -2),(4, 5)]` is ______
Find the adjoint of the matrix A = `[(2,3),(1,4)]`
If A-1 = `[(1,0,3),(2,1,-1),(1,-1,1)]` then, find A.
adj (AB) is equal to:
If A and B non-singular matrix then, which of the following is incorrect?
The matrix A = `[("a",-1,4),(-3,0,1),(-1,1,2)]` is not invertible only if a = _______.
If A = `[(2, 0, -1), (5, 1, 0), (0, 1, 3)]` and A−1 = `[(3, -1, 1), (α, 6, -5), (β, -2, 2)]`, then the values of α and β are, respectively.
If [abc] ≠ 0, then `(["a" + "b b" + "c c" + "a"])/(["b c a"])` = ____________.
If A is non-singular matrix and (A + l)(A - l) = 0 then A + A-1 = ______.
If A and Bare square matrices of order 3 such that |A| = 2, |B| = 4, then |A(adj B)| = ______.
If A = `[(0, 0, 1), (0, 1, 0), (1, 0, 0)]`, then A-1 = ______
If A, B are two square matries, such that AB = B, BA = A and n ∈ N then (A + B)n =
If matrix A = `[(3, -2, 4),(1, 2, -1),(0, 1, 1)]` and A–1 = `1/k` (adj A), then k is ______.
For a invertible matrix A if A(adjA) = `[(10, 0),(0, 10)]`, then |A| = ______.
If A = `[(1, 1, 0),(2, 1, 5),(1, 2, 1)]`, then a11A21 + a12A22 + a13A23 is equal to ______.
If matrix A = `[(1, 2),(4, 3)]`, such that AX = I, then X is equal to ______.
If A = `[(cos α, sin α),(-sin α, cos α)]`, then find α satisfying `0 < α < π/2`, when A + AT = `sqrt(2) l_2` where AT is transpose of A.
If A = `[(4, 3, 2),(-1, 2, 0)]`, B = `[(1, 2),(-1, 0),(1, -2)]`
Find (AB)–1 by adjoint method.
Solution:
AB = `[(4, 3, 2),(-1, 2, 0)] [(1, 2),(-1, 0),(1, -2)]`
AB = [ ]
|AB| = `square`
M11 = –2 ∴ A11 = (–1)1+1 . (–2) = –2
M12 = –3 A12 = (–1)1+2 . (–3) = 3
M21 = 4 A21 = (–1)2+1 . (4) = –4
M22 = 3 A22 = (–1)2+2 . (3) = 3
Cofactor Matrix [Aij] = `[(-2, 3),(-4, 3)]`
adj (A) = [ ]
A–1 = `1/|A| . adj(A)`
A–1 = `square`
Find the inverse of the matrix `[(1, 1, 1),(1, 2, 3),(3, 2, 2)]` by elementary column transformation.