Find the principal value of `cos^(-1) (sqrt3/2)`

Let `cos^(-1) (sqrt3/2) = y," Then " cos y = sqrt3/2 = cos (pi/6)` We know that the range of the principal value branch of cos−1 is `[0, pi] and cos (pi/6) = sqrt3/2` Therefore, the priciple value of `cos^(-1) (sqrt3/2) is pi/6`

Find the principal value of cos-1(32) - Mathematics

प्रश्न

Find the principal value of $\cos^{- 1} (\frac{\sqrt{3}}{2})$

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उत्तर

Let $\cos^{- 1} (\frac{\sqrt{3}}{2}) = y, Then \cos y = \frac{\sqrt{3}}{2} = \cos (\frac{π}{6})$

We know that the range of the principal value branch of cos⁻¹ is

$[0, π] and \cos (\frac{π}{6}) = \frac{\sqrt{3}}{2}$

Therefore, the priciple value of $\cos^{- 1} (\frac{\sqrt{3}}{2}) i s \frac{π}{6}$

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Inverse Trigonometric Functions

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अध्याय 2: Inverse Trigonometric Functions - Exercise 2.1 [पृष्ठ ४१]

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अध्याय 2 Inverse Trigonometric Functions
Exercise 2.1 | Q 2 | पृष्ठ ४१

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Find the principal value of cos-1(32) - Mathematics

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