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प्रश्न
Find the principal value of `cos^(-1) (sqrt3/2)`
उत्तर
Let `cos^(-1) (sqrt3/2) = y," Then " cos y = sqrt3/2 = cos (pi/6)`
We know that the range of the principal value branch of cos−1 is
`[0, pi] and cos (pi/6) = sqrt3/2`
Therefore, the priciple value of `cos^(-1) (sqrt3/2) is pi/6`
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