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प्रश्न
Assertion (A): The domain of the function sec–12x is `(-∞, - 1/2] ∪ pi/2, ∞)`
Reason (R): sec–1(–2) = `- pi/4`
पर्याय
Both A and R are true and R is the correct explanation of A.
Both A and R are true but R is not the correct explanation of A.
A is true but R is false.
A is false but R is true.
उत्तर
A is true but R is false.
Explanation:
sec–1x is defined if x ≤ −1 or x ≥ 1.
Hence, sec–12x will be defined if `x ≤ - 1/2` or `x ≥ 1/2`.
Hence, A is true.
The range of the function sec–1x is [0, π] − `{pi/2}`
R is false.
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