Advertisements
Advertisements
प्रश्न
If 10x = 64, what is the value of \[{10}^\frac{x}{2} + 1 ?\]
विकल्प
18
42
80
81
उत्तर
We have to find the value of `10^(x/2+1)`provided `10^x = 64`
So,
`10^(x/2 xx 1) = 10^(x xx1/2) xx 10^1`
`= 2sqrt(10^x) xx 10^1`
By substituting `10x = 64 `we get
`=2sqrt 64 xx 10^1`
`=2sqrt (8xx8 )xx10`
`=8xx10`
`= 80`
APPEARS IN
संबंधित प्रश्न
Assuming that x, y, z are positive real numbers, simplify the following:
`sqrt(x^3y^-2)`
Prove that:
`(3^-3xx6^2xxsqrt98)/(5^2xxroot3(1/25)xx(15)^(-4/3)xx3^(1/3))=28sqrt2`
Find the value of x in the following:
`2^(x-7)xx5^(x-4)=1250`
Find the value of x in the following:
`(13)^(sqrtx)=4^4-3^4-6`
If `5^(3x)=125` and `10^y=0.001,` find x and y.
If 24 × 42 =16x, then find the value of x.
The value of \[\left\{ 2 - 3 (2 - 3 )^3 \right\}^3\] is
If o <y <x, which statement must be true?
The positive square root of \[7 + \sqrt{48}\] is
Which of the following is equal to x?
