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In the expansion of (x + a)n if the sum of odd terms is denoted by O and the sum of even term by E. Then prove that 4OE = (x + a)2n – (x – a)2n - Mathematics

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प्रश्न

In the expansion of (x + a)n if the sum of odd terms is denoted by O and the sum of even term by E. Then prove that 4OE = (x + a)2n – (x – a)2n 

योग

उत्तर

4OE = (O + E)2 – (O – E)2

= [(x + a)n]2 – [(x – a)n]2

= [x + a]2n – [x – a]2n

Hence, 4OE = (x + a)2n – (x – a)2n

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अध्याय 8: Binomial Theorem - Exercise [पृष्ठ १४३]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 8 Binomial Theorem
Exercise | Q 15.(ii) | पृष्ठ १४३

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