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Prove that tan(π4+θ)-tan(π4-θ) = 2 tan 2θ - Mathematics

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प्रश्न

Prove that `tan (pi/4 + theta) - tan(pi/4 - theta)` = 2 tan 2θ

योग

उत्तर

`tan (pi/4 + theta) - tan(pi/4 - theta)` = `(tan  pi/4 + tan theta)/(1 - tan  pi/4 tan theta) - (tan  pi/4 - tan theta)/(1 + tan  pi/4 tan theta)`

= `(1 + tan theta)/(1 - tan theta) - (1 - tan theta)/(1 + tan theta)`

= `((1 + tan theta)^2 - (1 - tan theta)^2)/((1 - tan theta) (1 + tan theta))`

= `((1 + 2 tan theta + tan^2theta) - (1 - 2 tan theta + tan^2theta))/(1 - tan^2theta)`

= `(1 + 2 tan theta + tan^2theta - 1 + 2tan theta - tan^2theta)/(1 - tan^2theta)`

= `(4 tan theta)/(1 - tan^2theta)`

= `2 * (2 tan theta)/(1 - tan^2theta)`

= 2 tan 2θ 

shaalaa.com
Trigonometric Functions and Their Properties
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometry - Exercise 3.5 [पृष्ठ ११८]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 3 Trigonometry
Exercise 3.5 | Q 8 | पृष्ठ ११८

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