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प्रश्न
Find the values of `tan ((19pi)/3)`
उत्तर
`tan ((19pi)/3) = tan 19/3 xx 180`
= `tan 19/3 xx 360/2`
= `tan 19/6 (360^circ)`
= `tan 3 1/6 (360^circ)`
= `tan[3(360)^circ + 360^circ/6]`
= tan 60°
= `sqrt(3)`
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