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प्रश्न
Solve: 4x − 2 < 8, when x ∈ R
उत्तर
\[\text{ We have }, 4x - 2 < 8\]
\[ \Rightarrow 4x < 8 + 2 (\text{ Transposing } - 2 \text{ to the RHS })\]
\[ \Rightarrow 4x < 10\]
\[ \Rightarrow x < \frac{10}{4} (\text{ Dividing both the sides by } 4)\]
\[ \Rightarrow x < \frac{5}{2}\]
\[ x \in R\]
\[\text{ Then, the solution of the given inequation is } \left( - \infty , \frac{5}{2} \right) . \]
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