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प्रश्न
Write the structure of the major organic product in the following reaction:
\[\ce{CH3CH(Br)CH2CH3 + NaOH ->[water]}\]
उत्तर
\[\begin{array}{cc}
\ce{CH3 - CH - CH2CH3 + NaOH ->[H2O][Hydrolysis] CH3 - CH - CH2CH3 + NaBr + H2O}\\
|\phantom{........................................}|\phantom{......................}\\
\ce{\underset{2-Bromobutane}{Br}}\phantom{................................}\ce{\underset{Butan-2-ol}{OH}}\phantom{......................}
\end{array}\]
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संबंधित प्रश्न
Out of , which is more reactive towards SN1 reaction and why?
Write the structures of A, B and C in the following:
Which alkyl halide from the following pair would you expect to react more rapidly by an SN2 mechanism? Explain your answer.
CH3CH2CH2CH2Br or \[\begin{array}{cc}
\ce{CH3CH2CHCH3}\\
\phantom{...}|\\
\phantom{....}\ce{Br}\
\end{array}\]
Write the isomers of the compound having the formula C4H9Br.
Arrange the compounds of the following set in order of reactivity towards SN2 displacement:
1-Bromobutane, 1-Bromo-2, 2-dimethylpropane, 1-Bromo-2-methylbutane, 1-Bromo-3-methylbutane
Out of C6H5CH2Cl and C6H5CHClC6H5, which is more easily hydrolysed by aqueous KOH.
Which of the following pairs is/are correctly matched?
Reaction | Product | |
I | RX + AgCN | RNC |
II | RX + KCN | RCN |
III | RX + KNO2 | \[\begin{array}{cc} \phantom{.......}\ce{O}\\ \phantom{.....}/\\ \ce{R - N}\phantom{....}\\ \phantom{.....}\backslash\backslash\\ \phantom{.......}\ce{O} \end{array}\] |
IV | RX + AgNO2 | \[\ce{R-O-N=O}\] |
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Identify X and Y in the following sequence:
\[\ce{C2H5Br ->[X] Product ->[Y] C3H7NH2}\]
Which of the following undergoes nucleophilic substitution exclusively by SN1 mechanism?
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Reason: CN– is an ambident nucleophile.
Which reagent will you use for the following reaction?
\[\ce{CH3CH2CH2CH3 -> CH3CH2CH2CH2Cl + CH3CH2CHClCH3}\]
Which of the following statements are correct about the kinetics of this reaction?
(i) The rate of reaction depends on the concentration of only (b).
(ii) The rate of reaction depends on concentration of both (a) and (b).
(iii) Molecularity of reaction is one.
(iv) Molecularity of reaction is two.
Compound ‘A’ with molecular formula \[\ce{C4H9Br}\] is treated with aq. \[\ce{KOH}\] solution. The rate of this reaction depends upon the concentration of the compound ‘A’ only. When another optically active isomer ‘B’ of this compound was treated with aq. \[\ce{KOH}\] solution, the rate of reaction was found to be dependent on concentration of compound and \[\ce{KOH}\] both.
(i) Write down the structural formula of both compounds ‘A’ and ‘B’.
(ii) Out of these two compounds, which one will be converted to the product with inverted configuration.
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When CH3CH2CHCl2 is treated NaNH2 product formed is:-
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Convert bromoethane to propanamine.
An organic compound A with the molecular formula (+) C4H9Br undergoes hydrolysis to form (+) C4H9OH. Give the structure of A and write the mechanism of the reaction.