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प्रश्न
Draw a line segment of length `sqrt5` cm.
उत्तर
Construct a right-angled triangel OAB with
OA = 2 cm,
∠OAB = 90° and
AB = 1 cm
Using OB2 = OA2 + AB2
OB2 = 22 + 12
OB2 = 4 + 1
OB2 = 5
OB = `sqrt5`
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संबंधित प्रश्न
Rationalize the denominator.
`1/sqrt5`
Rationalize the denominator.
`1/(3 sqrt 5 + 2 sqrt 2)`
Simplify by rationalising the denominator in the following.
`(sqrt(3) + 1)/(sqrt(3) - 1)`
Simplify by rationalising the denominator in the following.
`(4 + sqrt(8))/(4 - sqrt(8)`
Simplify by rationalising the denominator in the following.
`(3sqrt(5) + sqrt(7))/(3sqrt(5) - sqrt(7)`
Simplify by rationalising the denominator in the following.
`(5sqrt(3) - sqrt(15))/(5sqrt(3) + sqrt(15)`
Simplify the following :
`sqrt(6)/(sqrt(2) + sqrt(3)) + (3sqrt(2))/(sqrt(6) + sqrt(3)) - (4sqrt(3))/(sqrt(6) + sqrt(2)`
If x = `((sqrt(3) + 1))/((sqrt(3) - 1)` and y = `((sqrt(3) - 1))/((sqrt(3) + 1)`, find the values of
x3 + y3
If x = `(1)/((3 - 2sqrt(2))` and y = `(1)/((3 + 2sqrt(2))`, find the values of
x3 + y3
Show that: `x^2 + 1/x^2 = 34,` if x = 3 + `2sqrt2`
