Advertisements
Advertisements
प्रश्न
Fill in the blank : If `int_0^"a" 3x^2*dx` = 8, then a = _______
उत्तर
`int_0^"a" 3x^2*dx` = 8
∴ `3[x^3/3]_0^"a"` = 8
∴ a3 = 23
∴ a = 2.
APPEARS IN
संबंधित प्रश्न
Evaluate : `int_0^(pi/4) sec^4x*dx`
Evaluate the following : `int_(-a)^(a) (x + x^3)/(16 - x^2)*dx`
`int_0^(log5) (e^x sqrt(e^x - 1))/(e^x + 3) * dx` = ______.
Evaluate the following : `int_0^pi (sin^-1x + cos^-1x)^3 sin^3x*dx`
Evaluate the following definite integrals: `int_0^1 (1)/(sqrt(1 + x) + sqrt(x))*dx`
Choose the correct alternative :
`int_"a"^"b" f(x)*dx` =
Solve the following : `int_1^2 (x + 3)/(x (x + 2))*dx`
Solve the following:
`int_1^3 x^2 log x*dx`
Solve the following : `int_1^2 x^2*dx`
Choose the correct alternative:
`int_4^9 ("d"x)/sqrt(x)` =
Evaluate:
`int_1^2 1/(x^2 + 6x + 5) dx`
`int_0^(π/2) (sin^2 x.dx)/(1 + cosx)^2` = ______.
`int_0^4 1/sqrt(4x - x^2)dx` = ______.
Evaluate the following definite intergral:
`int _1^3logxdx`
The principle solutions of the equation cos θ = `1/2` are ______.
Evaluate the following definite intergral:
`int_-2^3 1/(x+5)dx`
Solve the following.
`int_0^1 e^(x^2) x^3 dx`
Evaluate the following definite intergral:
`int_4^9 1/sqrtx dx`
Evaluate the following definite intergral:
`int_1^2(3x)/(9x^2-1).dx`
Evaluate the following definite intergral.
`int_4^9 1/sqrtx .dx`
