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प्रश्न
Find `"dy"/"dx"` if, y = log(log x)
उत्तर
y = log(log x)
Differentiating both sides w.r.t.x, we get
`"dy"/"dx" = "d"/"dx"` [log (log x)]
`= 1/(log "x") * "d"/"dx" (log "x")`
`= 1/(log "x") * 1/"x"`
∴ `"dy"/"dx" = 1/("x" * log "x")`
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