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प्रश्न
Find the following integrals:
`int(sqrtx - 1/sqrtx)^2 dx`
उत्तर
Let I = `int (sqrtx - 1/sqrtx)^2 dx`
`I= int (x + 1/x - 2) dx`
`I = int x dx + int 1/x dx - 2 int 1 dx`
`I= x^2/2 + log abs x - 2x + C`
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