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Find the integrals of the function: cos2x-cos2αcosx-cosα - Mathematics

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प्रश्न

Find the integrals of the function:

`(cos 2x - cos 2 alpha)/(cos x - cos alpha)`

बेरीज

उत्तर

Let `I = int ((cos 2x - cos 2alpha)/(cos x - cos alpha)) dx`

`= int ((2 cos^2 x - 1) - (2 cos^2 alpha - 1))/(cos x - cos alpha)  dx`

`= int (2(cos^2 x - cos^2 alpha))/ (cos x - cos alpha) dx`

`= int ((2 cos^2 x - 1) - (2 cos^2 alpha - 1))/(cos x - cos alpha) dx`

`= 2 int (cos x + cos alpha) dx`

 `= 2 int (cos x) dx + int (2 cos alpha) dx`

`= 2 sin + 2x cos alpha + C`

`= 2 (sin x + x cos alpha) + C`

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पाठ 7: Integrals - Exercise 7.3 [पृष्ठ ३०७]

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एनसीईआरटी Mathematics [English] Class 12
पाठ 7 Integrals
Exercise 7.3 | Q 13 | पृष्ठ ३०७

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