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प्रश्न
Find: `intsqrt(1 - sin 2x) dx, pi/4 < x < pi/2`
उत्तर
`I = int sqrt(1 - sin 2x) dx`
`I = int sqrt(sin^2 x + cos^2 x - 2sin x cos x) dx`
`I = int (sin x - cos x )dx`
`I = int sin x dx - int cos x dx`
`I = -cos x - sin x + "C"`
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