Advertisements
Advertisements
प्रश्न
Find the length of EC.
उत्तर
CD = 28cm
⇒ AB = 28cm
In right ΔABE,
tan30° = `"BE"/"AB"`
⇒ `(1)/sqrt(3) = "BE"/(28)`
⇒ BE = `(28)/sqrt(3)`
In right ΔABC,
tan60° = `"CB"/"AB"`
⇒ `sqrt(3) = "CB"/(28)`
⇒ CB = `28sqrt(3)`
∴ Length of EC
= CB + BE
= `28sqrt(3) + (28)/sqrt(3)`
= `(84 + 28)/sqrt(3)`
= `(112)/sqrt(3)`.
APPEARS IN
संबंधित प्रश्न
From the given figure,
find:
(i) cos x°
(ii) x°
(iii) `(1)/(tan^2 xx°) – (1)/(sin^2xx°)`
(iv) Use tan xo, to find the value of y.
If sin 3A = 1 and 0 < A < 90°, find cos 2A
Solve for x : tan2 (x - 5°) = 3
Find the value of 'A', if 2cos 3A = 1
If θ = 30°, verify that: 1 - sin 2θ = (sinθ - cosθ)2
In a right triangle ABC, right angled at C, if ∠B = 60° and AB = 15units, find the remaining angles and sides.
Find the value 'x', if:
Evaluate the following: tan(78° + θ) + cosec(42° + θ) - cot(12° - θ) - sec(48° - θ)
If cosθ = sin60° and θ is an acute angle find the value of 1- 2 sin2θ
If secθ= cosec30° and θ is an acute angle, find the value of 4 sin2θ - 2 cos2θ.
